lewisracing00
New member
Im looking to get an adjustable timing flywheel. Should I try the small diameter or go with the full size? Im running small bullring style tracks. Will the small one help or hurt?
I have tried and tested the smaller diameter wheels. You have to relocate the coil with a bracket that is usually supplied. I tried the Arc . The theory is the smaller dia. would bring the centrifugal rotating mass closer to center line making a heavier wheel feel lighter to the motor...The difference is very small if any on the dyno...
Can I say thanks to a post twice? Just because the dyno doesn't show it doesn't mean the advantage isn't there. I've tested this on the track with great results proving that less rotating mass equals kart seperation!!!!Sneaks always has to get in the discussion using facts.
A smaller diameter flywheel that has the same mass as a larger diameter f/w will have less inertia and will accelerate faster.
More horsepower? Maybe not.
Will the motor rev/accelerate quicker? I would say yes.
Facts w/Knowledge will beat a 'WAG' on any track...every day!Sneaks always has to get in the discussion using facts.
....Now heres the tricky part...3 pounds rotated to 6000rpms should require the same amount of energy no matter what the diameter...So whats going on ?
Not true ... the torque (energy) required to accelerate a rotating mass (flywheel) is dependent on the mass (flywheel weight), the distribution of that mass, and the radius of gyration of that mass (radius or diameter of flywheel). Assuming a homogenous distribution of mass between two flywheels of equal weight, the flywheel with the larger diameter (radius of gyration) will require more torque to accelerate and decelerate at a given rpm.
If the mass of the flywheel is expressed as M and the radius of gyration is expressed as R then the formula for determining the moment of inertia is (M)(R)(R) = I
So you can see from the formula that the torque required to accelerate the flywheel increases by the square of the radius of the flywheel .. as an example, for a given mass, a flywheel with a 12" diameter would require 4 times the torque to accelerate as a flywheel with a 6" diameter.
Here's the problem , Flywheels are not homogenous, They are different shapes with different friction values while spinning and I believe your formula is only true in a zero gravity environment.
Actually the flywheels used in our application are fairly homogenous in terms of the distribution of the mass. Also there is very little frictional losses associated with the flywheels in our application ... only air and magnetic resistance, and those are fairly constant between the various flywheels, regardless of their mass or weight. Most of the frictional losses are attributed to those generated internally within the engine and are a not affected by flywheel selection or design.
Neither zero gravity, nor earth gravity, have any effect on the formula ... The laws of mass and inertia are not affected by gravity. Mass is a measurement of the amount of matter something contains, while Weight is the measurement of the pull of gravity on an object.
While the weight of a object is a function of the strength of gravity, the mass of an object is constant for any location, and not an associated function of gravity.
But I think my real problem here is one formula does not cover everything that's happening.